# Solutions (8th Ed Structural Analysis) Chapter 8

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- 1.267 For (1) (2) For (3) (4) Boundary conditions: at From Eq. (2) Due to symmetry: at From Eq. (3) Continuity conditions: at (5) at x1 = x2 = a dv1 dx1 = dv2 dx2 C1a # C4 = Pa3 2 - Pa3 L 2 Pa3 6 + C1a = Pa3 2 - Pa3 L 2 + C4 x1 = x2 = av1 = v2 C3 = PaL 2 0 = Pa L 2 + C3 x1 = L 2 dv1 dx1 = 0 C2 = 0 x = 0v1 = 0 EIv1 = Pax1 2 2 = C3x1 + C4 EI dv1 dx1 = Pax1 + C1 EI d2 v1 dx1 2 = Pa M1(x) = Pa EIv1 = Px1 2 6 C1x1 + C1 EI dv1 dx1 = Px1 2 2 + C1 EI d2 v1 dx1 2 = Px1 M1(x) = Px1 EI d2 v dx2 = M(x) *8–1. Determine the equations of the elastic curve for the beam using the and coordinates. Specify the slope at A and the maximum deflection. EI is constant. x2x1 © 2012 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved.This material is protected under all copyright laws as they currently exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. A B PP L x2 x1 a a

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